Statistics & Probability Β· playable

Lay every combo in a grid.

When two things happen at once, the probability isn't a mystery β€” it's just counting squares.

Start here
The whole idea

Every possibility gets its own square.

Flip two coins, or roll two dice, and you've made a combined event β€” two things happening together. Draw a grid with one event down the side and the other across the top, and every square is one way it could turn out.

Once the grid is full, probability stops being scary. You just count the squares you want, count all the squares, and put one over the other. That's the entire trick, and this page is going to let you build it with your own hands.

A few words first

Four words, then you're set.

These come up on every probability page, so let's pin them down once, in plain language:

Keep those four in your pocket. Probability of the thing you want is always just favourable outcomes Γ· total outcomes β€” the shaded squares over all the squares.

Try it β€” the outcome table

Build the grid, pick a target, read the odds.

Choose which two events happen together. The table fills with every combination. Then pick a target and watch the shaded squares β€” and the probability β€” appear. Click any single square to see its own tiny chance.

What's happening together?
Favourable squares
β€”
Total squares
β€”
Probability
β€”

Pick a target above, or click one square to spotlight a single outcome.

Worked example Β· two coins

Two coins make four squares.

Set the table above to Two coins and count with me. Each coin can land two ways, heads (H) or tails (T). Put the first coin down the side and the second across the top, and you get a tiny 2Γ—2 grid β€” four squares in all:

HH   HT   TH   TT  β†’  4 equally likely outcomes

Want both heads? Only one square says HH. So the probability is

P(both heads) = 14 = 0.25 = 25%

Now try the target "exactly one head" in the table. Two squares fit β€” HT and TH β€” so it's 24, which is the same as 12. And "at least one head" covers three squares (HH, HT, TH), so it's 34. Same grid, different shading β€” that's all a probability question ever is.

Notice how each square is equally likely: with fair coins, no combination is special. That's why we're allowed to just count. If the squares weren't all equally likely, counting alone wouldn't be enough β€” but for fair coins and fair dice, it always is.

Worked example Β· two dice

Two dice make thirty-six squares.

Switch the table to Two dice. Each die shows 1 to 6, so the grid grows to 6 rows by 6 columns β€” 6 Γ— 6 = 36 squares, one for every pair like (3,5) or (6,1). That's the whole sample space for a pair of dice.

Here's the classic question: what's the chance the two dice add up to 7? Highlight the "sum = 7" target and count the shaded squares. You'll find exactly six of them, running in a neat diagonal:

(1,6)   (2,5)   (3,4)   (4,3)   (5,2)   (6,1)
P(sum = 7) = 636 = 16 β‰ˆ 0.167 β‰ˆ 16.7%

Six favourable squares out of thirty-six total. Simplify 636 by dividing both by 6 and you get 16 β€” the same odds as rolling a single die and getting a 4.

Try a few more targets and watch the diagonals shift. "Doubles" (both dice the same) is another 6 squares β€” 636 = 16. "Snake eyes" (sum = 2) is a lonely single square, 136 β€” the rarest thing on the board. And "at least one 6" lights up a whole row and column, 11 squares, 1136. The grid never lies: every question is just how many squares fit.

The big pattern

Why the possibilities multiply.

Here's the shortcut that saves you from ever drawing a giant grid by hand. To get the total number of squares, you multiply the number of ways each event can turn out. Two coins: 2 Γ— 2 = 4. Two dice: 6 Γ— 6 = 36. A coin and a die: 2 Γ— 6 = 12.

Why multiply? Because for every one of the first event's outcomes, the second event can still do all of its outcomes. Each of the 2 coin results opens up all 6 die results, so you stack 6 on top of 6 β€” that's the grid growing sideways and downward at the same time. Add a third event and it multiplies again. Build a lineup below and watch the total climb:

Add an event to start the grid.
 
0
total possible outcomes

Each coin multiplies the total by 2; each die multiplies it by 6. The numbers get big fast β€” that's why a grid is your friend and a shortcut is your saviour.

Mixing it up Β· coin + die

The two events don't have to match.

Nothing says both events have to be the same. Toss a coin and roll a die together and you've combined a 2-outcome event with a 6-outcome event. Set the table to Coin + die and you'll see a 2Γ—6 grid β€” 2 Γ— 6 = 12 squares, from (H,1) all the way to (T,6).

Want heads and a 6 at the same time? Only one square out of twelve matches:

P(heads and a 6) = 112 β‰ˆ 0.083 β‰ˆ 8.3%

Want just heads (any number)? That's a whole row β€” 6 squares β€” so 612 = 12, exactly what you'd expect from a coin on its own. The grid quietly agrees with common sense, which is a good sign you're counting right.

This is the real power of the grid: it doesn't care what the two events are. Coin and die, die and spinner, card and coin β€” lay them on two axes, fill the squares, count what you want. The method never changes.

Mini-challenge

Your turn β€” no grid to peek at.

Four quick questions. Think in squares: favourable over total. Tap your answer to see if it lands.

Carry this with you

The whole idea, in three moves.

1

Lay the grid

One event down the side, the other across the top. Every square is one outcome.

2

Multiply the totals

Ways for event one times ways for event two. 2Γ—2=4, 6Γ—6=36, 2Γ—6=12.

3

Count and divide

Favourable squares over total squares β€” then simplify the fraction. That's the probability.